# SAT Math Multiple Choice Practice Question 562: Answer and Explanation

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**Question: 562**

**19.**

If *C* and *D* represent digits in the correctly worked multiplication problem above, then *C* + *D* =

A. 2

B. 7

C. 8

D. 13

E. 15

**Correct Answer:** C

**Explanation:**

**C** This is a multiplication problem, so to find *C* we need to find out what digit times 6 results in a product that ends in 8. The multiples of 6 that end in 8 are 18 and 48. If *C* is 3, then 6 × 3 is 18, and we carry the 1. The *C* in answer 94*C*8 also must be 3: 6 × 7 = 42, plus the 1 we carried, is 43. This gets a 3 into the *C* spot, (using 8 as a multiplier does not lead to an 8 in the *C* spot in the product). Now we need to find the value of *D*. Since we are carrying the 4 from the last multiplication, 6 × *D* must result in a product of 0. Only 6 × 5 = 30 fits, so *D* = 5. Finally, find the sum of *C* + *D*: 3 + 5 = 8, answer C.